The product (A) of the given oxymercuration-d | vedclass

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(A) The reaction is an alkoxymercuration-demercuration of $1$-methylcyclohexene using mercuric acetate $Hg(OAc)_2$ and methanol $CH_3OH$,followed by r

Vedclass · Accepted Answer

$1-$methoxy$-1-$methylcyclohexane

Vedclass · Answer

(A) The reaction is an alkoxymercuration-demercuration of $1$-methylcyclohexene using mercuric acetate $Hg(OAc)_2$ and methanol $CH_3OH$,followed by reduction with $NaBH_4$.This reaction follows Markovnikov's rule,where the nucleophile (methoxy group,$-OCH_3$) attacks the more substituted carbon atom of the double bond.In $1$-methylcyclohexene,the carbon at position $1$ is more substituted than the carbon at position $2$.Therefore,the methoxy group attaches to the $C-1$ position,resulting in $1$-methoxy-$1$-methylcyclohexane as the major product.

The product $(A)$ of the given oxymercuration-demercuration reaction is:

Similar Questions

Alkene can be prepared from alkyl halide by the following reagent: $R-CH_2-CH_2-X + \text{Base} \to \text{Alkene} + \text{Base-H} + X^-$

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The major product formed in the following reaction is:

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