The product (C) in the following sequence of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. The starting material is propylbenzene. Oxidation with $KMnO_4-KOH$ followed by acidification $(H_3O^+)$ converts the alkyl side chain into a

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) $1$. The starting material is propylbenzene. Oxidation with $KMnO_4-KOH$ followed by acidification $(H_3O^+)$ converts the alkyl side chain into a carboxylic acid group,yielding benzoic acid $(B)$.$2$. Benzoic acid is then subjected to electrophilic aromatic substitution with $Br_2$ in the presence of $FeBr_3$. Since the $-COOH$ group is meta-directing,the product $(C)$ is $m$-bromobenzoic acid.$3$. The structure of $m$-bromobenzoic acid contains a benzene ring (which has $3$ $\pi$ bonds) and a carbonyl group ($C=O$,which has $1$ $\pi$ bond).$4$. Total $\pi$ bonds $= 3 + 1 = 4$.

The product $(C)$ in the following sequence of reactions has . . . . . . . . $\pi$ bonds.

Similar Questions

Which of the following is the strongest acid?

Oxalic acid reacts with concentrated $H_2SO_4$ to give a mixture of two gases. When this mixture is passed through caustic potash,one of the gases is absorbed. What is the product formed by the absorbed gas with caustic potash?

Which of the following acids will form an $(a)$ anhydride on heating and $(b)$ an acid imide on strong heating with ammonia?

Rearrange the following in the increasing order of acidic strength:
$(i)$ benzoic acid $(ii)$ $p$-methoxybenzoic acid $(iii)$ $o$-methoxybenzoic acid

Cinnamic acid is formed when $C_6H_5CHO$ condenses with $(CH_3CO)_2O$ in the presence of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module