The product 6-oxoheptanal is formed by the re | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $6-$oxoheptanal is $CH_3-C(=O)-CH_2-CH_2-CH_2-CH_2-CHO$.Reductive ozonolysis of a cyclic alkene involves the cleavage of the double bond to form a

Vedclass · Accepted Answer

$1-$methylcyclohexene

Vedclass · Answer

(A) $6-$oxoheptanal is $CH_3-C(=O)-CH_2-CH_2-CH_2-CH_2-CHO$.Reductive ozonolysis of a cyclic alkene involves the cleavage of the double bond to form a dicarbonyl compound.For $1-$methylcyclohexene,the double bond is between $C_1$ and $C_2$. Cleavage results in a $7-$carbon chain with a ketone at $C_2$ and an aldehyde at $C_7$ (numbering from the ketone end),which corresponds to $6-$oxoheptanal.Therefore,the correct reactant is $1-$methylcyclohexene.

The product $6-$oxoheptanal is formed by the reductive ozonolysis of:

Similar Questions

What is the major product expected from the following reaction?
Where $D$ is an isotope of hydrogen.

What are the $IUPAC$ nomenclature rules for naming alkenes?

Which of the following is obtained on oxidation of $prop-1-ene$ with acidic $KMnO_4$?

The product $(B)$ in the given reaction is:

Product $(P)$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module