The product (R) in the following synthetic sc | vedclass

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(B) Chlorobenzene undergoes electrophilic aromatic substitution (nitration) with conc. $HNO_3$ and conc. $H_2SO_4$ to form $p$-nitrochlorobenzene as t

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$4-$nitrophenol

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(B) Chlorobenzene undergoes electrophilic aromatic substitution (nitration) with conc. $HNO_3$ and conc. $H_2SO_4$ to form $p$-nitrochlorobenzene as the major product $(P)$ and $o$-nitrochlorobenzene as the minor product $(Q)$.In the next step,$p$-nitrochlorobenzene $(P)$ reacts with $NaOH$ at $443 \ K$ followed by acidification $(H^+)$. The presence of the electron-withdrawing $-NO_2$ group at the para position activates the ring towards nucleophilic aromatic substitution,replacing the $-Cl$ atom with an $-OH$ group to form $p$-nitrophenol $(R)$.

The product $(R)$ in the following synthetic scheme is

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