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Question

(A) The reaction involves the acid-catalyzed dehydration of $2,2$-dimethylcyclohexanol. $1$. Protonation of the hydroxyl group occurs to form a good l

Vedclass · Accepted Answer

$1,2-$dimethylcyclohexene

Vedclass · Answer

(A) The reaction involves the acid-catalyzed dehydration of $2,2$-dimethylcyclohexanol. $1$. Protonation of the hydroxyl group occurs to form a good leaving group $(-OH_2^+)$. $2$. Loss of water generates a secondary $(2^{\circ})$ carbocation at the $C1$ position. $3$. $A$ $1,2$-methyl shift occurs from $C2$ to $C1$ to form a more stable tertiary $(3^{\circ})$ carbocation at $C2$. $4$. Elimination of a proton from the adjacent carbon ($C1$ or $C3$) leads to the formation of an alkene. $5$. According to Zaitsev's rule, the more substituted alkene is the major product. Elimination of a proton from $C1$ gives $1,2$-dimethylcyclohexene (tetrasubstituted), which is more stable than $1,6$-dimethylcyclohexene (trisubstituted) formed by elimination from $C3$. Therefore, the major product $P$ is $1,2$-dimethylcyclohexene.

The product $P$ is :

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