The product obtained from the reaction is:

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(A) The given reaction is a nucleophilic substitution reaction $(S_N2)$.In the reactant,$4$-bromobenzyl chloride,there are two halogen atoms: $Br$ att

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$4-$Bromophenylacetonitrile

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(A) The given reaction is a nucleophilic substitution reaction $(S_N2)$.In the reactant,$4$-bromobenzyl chloride,there are two halogen atoms: $Br$ attached to the benzene ring and $Cl$ attached to the side chain $(CH_2Cl)$.$NaCN$ acts as a nucleophile $(CN^-)$. The $Cl$ atom in the $CH_2Cl$ group is part of an alkyl halide (specifically a primary benzylic halide),which is highly reactive towards nucleophilic substitution.In contrast,the $Br$ atom is directly attached to the benzene ring (aryl halide),which is inert towards nucleophilic substitution under these conditions due to the partial double-bond character of the $C-X$ bond.Therefore,the $CN^-$ nucleophile will selectively replace the $Cl$ atom in the $CH_2Cl$ group to form $4$-bromophenylacetonitrile $(Br-C_6H_4-CH_2CN)$.

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