The product obtained from the reaction is:

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Question

(A) The reaction involves $p$-bromobenzyl chloride reacting with $NaCN$ in ethanol. $NaCN$ is a nucleophile that undergoes a nucleophilic substitution

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$Br-C_6H_4-CH_2CN$

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(A) The reaction involves $p$-bromobenzyl chloride reacting with $NaCN$ in ethanol. $NaCN$ is a nucleophile that undergoes a nucleophilic substitution reaction $(S_N2)$ with the primary alkyl halide group $(-CH_2Cl)$. The aryl bromide ($-Br$ attached directly to the benzene ring) is much less reactive towards nucleophilic substitution due to the partial double bond character of the $C-Br$ bond and the electron-rich nature of the benzene ring. Therefore,the $-Cl$ atom is replaced by the $-CN$ group,while the $-Br$ atom remains unaffected. The product is $p$-bromophenylacetonitrile $(Br-C_6H_4-CH_2CN)$.

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