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Question

(A) The reactant is $3-(hydroxymethyl)cyclohexan-1-ol$. The reagent $Na_2Cr_2O_7 / H_2SO_4$ is a strong oxidizing agent (Jones reagent). It oxidizes p

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$3-$oxocyclohexanecarboxylic acid

Vedclass · Answer

(A) The reactant is $3-(hydroxymethyl)cyclohexan-1-ol$. The reagent $Na_2Cr_2O_7 / H_2SO_4$ is a strong oxidizing agent (Jones reagent). It oxidizes primary alcohols to carboxylic acids and secondary alcohols to ketones. Therefore,the $1^\circ$ alcohol group $(-CH_2OH)$ is oxidized to a carboxylic acid $(-COOH)$ and the $2^\circ$ alcohol group $(-OH)$ is oxidized to a ketone $(=O)$. The final product is $3-oxocyclohexanecarboxylic acid$.

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