The product of the following reaction is: CH_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given reaction is Oxymercuration-Demercuration $(OMDM)$. $1$. This reaction involves the Markovnikov addition of water ($H$ and $OH$) across t

Vedclass · Accepted Answer

$CH_3-C(CH_3)_2-CH(OH)-CH_3$

Vedclass · Answer

(A) The given reaction is Oxymercuration-Demercuration $(OMDM)$. $1$. This reaction involves the Markovnikov addition of water ($H$ and $OH$) across the double bond. $2$. Crucially,no carbocation rearrangement occurs in this process because a bridged mercurinium ion intermediate is formed. $3$. The $-OH$ group adds to the more substituted carbon of the double bond,and the $-H$ atom adds to the less substituted carbon. $4$. Therefore,$3,3$-dimethyl-$1$-butene $(CH_3-C(CH_3)_2-CH=CH_2)$ reacts to form $3,3$-dimethyl-$2$-butanol $(CH_3-C(CH_3)_2-CH(OH)-CH_3)$.

The product of the following reaction is: $CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow[(ii) NaBH_4]{(i) Hg(OAc)_2, H_2O}$

Similar Questions

$CH_2=CH-CH_2-CH_3 \xrightarrow{H^{+}/\Delta} \text{Major product}$. Identify the major product in the above reaction.

What is the product of the following reaction?

Explain the preparation of alkenes from alcohols by acidic dehydration.

How many propenyl radicals are possible from propene?

The boiling point (in $K$) of $cis-but-2-ene$ and dipole moment (in $D$) of $trans-but-2-ene$ are respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module