The product of the reaction will be :

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(C) The given reaction is a Perkin condensation reaction. In this reaction,an aromatic aldehyde reacts with an acid anhydride in the presence of the s

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$O_2N-C_6H_4-CH=C(C_6H_5)-COOH$

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(C) The given reaction is a Perkin condensation reaction. In this reaction,an aromatic aldehyde reacts with an acid anhydride in the presence of the sodium salt of the corresponding acid. The general reaction is: $Ar-CHO + (R-CH_2-CO)_2O \xrightarrow{R-CH_2-COONa/\Delta} Ar-CH=C(R)-COOH$. Here,$Ar = p-NO_2-C_6H_4-$ and $R = C_6H_5-$. Substituting these into the general formula,we get the product as $p-NO_2-C_6H_4-CH=C(C_6H_5)-COOH$.

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