The product of this reaction should be

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(D) The reaction involves the treatment of $2-$phenylpropanal with $D_2O$ in the presence of a base $(OD^-)$. This is an example of base-catalyzed ket

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(D) The reaction involves the treatment of $2-$phenylpropanal with $D_2O$ in the presence of a base $(OD^-)$. This is an example of base-catalyzed keto-enol tautomerism followed by deuterium exchange. The $\alpha$-hydrogen atom (the hydrogen attached to the carbon adjacent to the carbonyl group) is acidic. The base $OD^-$ abstracts this $\alpha$-proton to form an enolate ion. This enolate ion then picks up a deuteron $(D^+)$ from the $D_2O$ solvent to form the deuterated product. Thus,the $\alpha$-hydrogen is replaced by deuterium $(D)$. The structure of the product is $C_6H_5-CH(CH_3)-CDO$.

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