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(B) $1$. The reaction of nitrobenzene with $Sn/HCl$ is a reduction reaction that converts the nitro group $(-NO_2)$ into an amino group $(-NH_2)$,form

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$X$: Aniline,$Y$: Bromobenzene

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(B) $1$. The reaction of nitrobenzene with $Sn/HCl$ is a reduction reaction that converts the nitro group $(-NO_2)$ into an amino group $(-NH_2)$,forming aniline $(X)$.$2$. Aniline reacts with $NaNO_2/HCl$ at low temperatures $(0-5 \ ^\circ C)$ to undergo diazotization,forming benzenediazonium chloride.$3$. The subsequent reaction with $CuBr$ (Sandmeyer reaction) replaces the diazonium group with a bromine atom,resulting in the formation of bromobenzene $(Y)$.

The products $X$ and $Y$ in the following reaction sequence are:

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Identify $X$ and $Y$ in the following reactions:

Which of the following statements is true?
$1)$ Tertiary amines react with acid chlorides.
$2)$ $N$-ethylbenzene sulphonamide is soluble in alkali.
$3)$ $N,N$-diethylbenzene sulphonamide is soluble in alkali.
$4)$ Tertiary amines react with Hinsberg's reagent.

Which of the following reacts with $CHCl_3$ and $KOH$ to produce $RNC$?

Consider the following reactions and identify the correct reaction.

Reduction of nitroalkanes in neutral medium (e.g.,$Zn / NH_4Cl$) forms mainly

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