The quantity X = frac{varepsilon_0 LV}{t},whe | vedclass

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(D) We know that the capacitance $C$ of a parallel plate capacitor is given by $C = \frac{\varepsilon_0 A}{d}$.Since $A$ has dimensions of $L^2$ and $

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(D) We know that the capacitance $C$ of a parallel plate capacitor is given by $C = \frac{\varepsilon_0 A}{d}$.Since $A$ has dimensions of $L^2$ and $d$ has dimensions of $L$,the dimensions of $\varepsilon_0 L$ are equivalent to the dimensions of capacitance $C$.Substituting this into the expression for $X$:$X = \frac{(\varepsilon_0 L) V}{t} = \frac{C V}{t}$.Since $Q = CV$,we have $X = \frac{Q}{t}$.The rate of flow of charge $Q$ with respect to time $t$ is defined as current $I$.Therefore,the dimensions of $X$ are the same as those of current.

The quantity $X = \frac{\varepsilon_0 LV}{t}$,where $\varepsilon_0$ is the permittivity of free space,$L$ is length,$V$ is potential difference,and $t$ is time. The dimensions of $X$ are the same as those of:

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