The quantity of CO_2 in 500 mL of soda water | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Pressure of $CO_2$ $(p)$ $= 3.34 \ bar = 3.34 	imes 10^5 \ Pa$. Henry's law constant $(K_H)$ for $CO_2$ at $298 \ K$ is $1.67 	imes 10^8

Vedclass · Accepted Answer

$2.442$

Vedclass · Answer

(A) Given: Pressure of $CO_2$ $(p)$ $= 3.34 \ bar = 3.34 	imes 10^5 \ Pa$. Henry's law constant $(K_H)$ for $CO_2$ at $298 \ K$ is $1.67 	imes 10^8 \ Pa$. According to Henry's law,$p = K_H 	imes x$,where $x$ is the mole fraction of $CO_2$. $x = \frac{p}{K_H} = \frac{3.34 	imes 10^5 \ Pa}{1.67 	imes 10^8 \ Pa} = 2 	imes 10^{-3}$. Volume of water $= 500 \ mL$. Since density of water is $1 \ g/mL$,mass of water $= 500 \ g$. Moles of water $(n_{H_2O})$ $= \frac{500 \ g}{18 \ g/mol} = 27.78 \ mol$. Since $x = \frac{n_{CO_2}}{n_{CO_2} + n_{H_2O}} \approx \frac{n_{CO_2}}{n_{H_2O}}$,we have $n_{CO_2} = x 	imes n_{H_2O} = 2 	imes 10^{-3} 	imes 27.78 \ mol = 0.05556 \ mol$. Mass of $CO_2 = n_{CO_2} 	imes 	ext{Molar mass of } CO_2 = 0.05556 \ mol 	imes 44 \ g/mol = 2.4446 \ g \approx 2.442 \ g$.

The quantity of $CO_2$ in $500 \ mL$ of soda water when packed under $3.34 \ bar$ $CO_2$ pressure at $298 \ K$ in $g$ is

Similar Questions

In which of the following salts,the solubility increases appreciably with an increase in temperature?

Which of the following statement$(s)$ is/are correct regarding the solubility of solid $I_2$?

Which of the following statements is correct regarding Henry's law?

Identify from the following salts the one whose solubility in water decreases with an increase in temperature.

What is the solubility of oxygen gas in $100 \, cm^3$ of water at $293 \, K$ (in $, cm^3$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module