The quantum numbers $n = 2, l = 1$ represent:

The two electrons have the following set of quantum numbers:
$P = 3, 2, -2, +1/2$
$Q = 3, 0, 0, +1/2$
Which of the following statements is true?

Which electronic arrangement shows the ground state of an element?

The energy of an electron of $2p_y$ orbital is

Which of the following rules is violated by the given electronic configuration?

$A$ hydrogen atom has only one electron,so mutual repulsion between electrons is absent. However,in multielectron atoms,mutual repulsion between the electrons is significant. How does this affect the energy of an electron in the orbitals of the same principal quantum number in multielectron atoms?