The radii of a frustum of a cone are 10 , cm | vedclass

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(C) Given: Radii of the frustum are $R = 10 \, cm$ and $r = 7 \, cm$. The height $h = 4 \, cm$.First,we calculate the slant height $l$ of the frustum

Vedclass · Accepted Answer

$85$

Vedclass · Answer

(C) Given: Radii of the frustum are $R = 10 \, cm$ and $r = 7 \, cm$. The height $h = 4 \, cm$.First,we calculate the slant height $l$ of the frustum using the formula $l = \sqrt{h^2 + (R - r)^2}$.Substituting the values: $l = \sqrt{4^2 + (10 - 7)^2} = \sqrt{16 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5 \, cm$.The curved surface area of a frustum of a cone is given by the formula $CSA = \pi (R + r) l$.Substituting the values: $CSA = \pi (10 + 7) 	imes 5 = \pi (17) 	imes 5 = 85\pi \, cm^2$.Thus,the curved surface area is $85\pi \, cm^2$.

The radii of a frustum of a cone are $10 \, cm$ and $7 \, cm$. If its height is $4 \, cm$,its curved surface area is $\dots \dots \dots \pi \, cm^2$.

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