The radii of the first Bohr orbit of H (r_{H} | vedclass

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Question

(C) The radius of the $n^{th}$ Bohr orbit is given by the formula: $r_n = 0.529 	imes \frac{n^2}{Z} \ \mathring{A}$.
For the first Bohr orbit,$n = 1

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$r_{H} > r_{He^{+}} > r_{Li^{2+}}$

Vedclass · Answer

(C) The radius of the $n^{th}$ Bohr orbit is given by the formula: $r_n = 0.529 	imes \frac{n^2}{Z} \ \mathring{A}$.
For the first Bohr orbit,$n = 1$,so $r \propto \frac{1}{Z}$,where $Z$ is the atomic number.
The atomic numbers are: $Z_H = 1$,$Z_{He^{+}} = 2$,and $Z_{Li^{2+}} = 3$.
Since the radius is inversely proportional to the atomic number $(Z)$,a higher atomic number results in a smaller radius.
Therefore,the order of radii is $r_H > r_{He^{+}} > r_{Li^{2+}}$.

The radii of the first Bohr orbit of $H$ $(r_{H})$,$He^{+}$ $(r_{He^{+}})$ and $Li^{2+}$ $(r_{Li^{2+}})$ are in the order

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