The radii of the top and bottom of a bucket o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given,the radius of the top of the bucket,$R = 28 \, cm$.The radius of the bottom of the bucket,$r = 7 \, cm$.The slant height of the bucket,$l =

Vedclass · Accepted Answer

$4950$

Vedclass · Answer

(B) Given,the radius of the top of the bucket,$R = 28 \, cm$.The radius of the bottom of the bucket,$r = 7 \, cm$.The slant height of the bucket,$l = 45 \, cm$.Since the bucket is in the form of a frustum of a cone,the curved surface area is given by the formula:$	ext{Curved Surface Area} = \pi l (R + r)$Substituting the given values:$	ext{Curved Surface Area} = \frac{22}{7} 	imes 45 	imes (28 + 7)$$= \frac{22}{7} 	imes 45 	imes 35$$= 22 	imes 45 	imes 5$$= 22 	imes 225 = 4950 \, cm^2$.Thus,the curved surface area of the bucket is $4950 \, cm^2$.

The radii of the top and bottom of a bucket of slant height $45 \, cm$ are $28 \, cm$ and $7 \, cm$,respectively. The curved surface area of the bucket is (in $cm^2$)

Similar Questions

The Total Surface Area $(TSA)$ of a cylinder is equal to $\ldots \ldots$

Curved surface area of a cone = ....................

Total surface area of a closed cube with length $4 \, cm$ is $\ldots \ldots \ldots cm^{2}$.

$CSA$ of a cylindrical tank with diameter $2.1 \, m$ and height $5 \, m$ is $\ldots \ldots \ldots \ldots \, m^2$.

$A$ cylinder is closed at both the ends by hemispheres. The radius of the cylinder is $7 \, cm$ and the total height of the article is $34 \, cm$. Find the total surface area of the article. (in $cm^2$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module