(C) The number of half-lives $n$ is calculated as: $n = \frac{\text{Total time}}{\text{Half-life}} = \frac{49.2}{12.3} = 4$. The remaining amount $N_t

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(C) The number of half-lives $n$ is calculated as: $n = \frac{\text{Total time}}{\text{Half-life}} = \frac{49.2}{12.3} = 4$. The remaining amount $N_t$ is given by the formula: $N_t = N_0 \times (1/2)^n$. Substituting the values: $N_t = 32 \times (1/2)^4 = 32 \times \frac{1}{16} = 2 \ mg$.

Class 12 Chemistry Nuclear Chemistry Rate of decay and Half-life

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The radioisotope,tritium $({}_1^3H)$ has a half-life of $12.3 \ years$. If the initial amount of tritium is $32 \ mg$,how many milligrams of it would remain after $49.2 \ years$?

A
$8$
B
$1$
C
$2$
D
$4$

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Nuclear Chemistry

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Rate of decay and Half-life

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The half-life period of a radioactive substance is $140 \ days$. After how much time will $15 \ g$ decay from a $16 \ g$ sample of it?

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The radioisotope,tritium $({}_1^3H)$ has a half-life of $12.3 \ years$. If the initial amount of tritium is $32 \ mg$,how many milligrams of it would remain after $49.2 \ years$?

Similar Questions

If $3/4$ of a radioactive element disintegrates in $2$ hours,its half-life would be

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