The radius of a circular loop is $r$ and a current $i$ is flowing in it. The equivalent magnetic moment will be

$A$ small bar magnet experiences a torque of $0.016 \ Nm$ when placed with its axis at $30^{\circ}$ with an external magnetic field of $0.04 \ T$. If the bar magnet is replaced by a solenoid of cross-sectional area $1 \ cm^2$ and $1000$ turns, having the same magnetic moment as that of the bar magnet, then the current flowing through the solenoid is: (in $A$)

What is the magnetic moment due to the given current distribution?

The magnetic moment of a current $(i)$ carrying circular coil of radius $(r)$ and number of turns $(n)$ varies as

The magnetic moment of a current $(I)$ carrying circular coil of radius '$r$' and number of turns '$n$' depends on

If the number of turns,area,and current through a coil are given by $N$,$A$,and $I$ respectively,then its magnetic moment will be: