(C) The capacitance $C$ of an isolated spherical conductor of radius $R$ is given by the formula: $C = 4\pi \varepsilon_0 R$.We know that $\frac{1}{4\

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(C) The capacitance $C$ of an isolated spherical conductor of radius $R$ is given by the formula: $C = 4\pi \varepsilon_0 R$.We know that $\frac{1}{4\pi \varepsilon_0} = 9 \times 10^9\,N\cdot m^2/C^2$,so $4\pi \varepsilon_0 = \frac{1}{9 \times 10^9}$.Given $C = 1/9\,F$.Substituting the values into the formula: $R = \frac{C}{4\pi \varepsilon_0} = C \times (9 \times 10^9)$.$R = (1/9) \times (9 \times 10^9) = 10^9\,m$.Therefore,the radius of the sphere is $10^9\,m$.

Class 12 Physics Electrostatic Potential and Capacitance Basic of Capacitor and type of capacitor (Spherical, Cylindrical)

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The radius of a metallic sphere if its capacitance is $1/9\,F$,is

A
$10^6\,m$
B
$10^7\,m$
C
$10^9\,m$
D
$10^8\,m$

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Electrostatic Potential and Capacitance

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Basic of Capacitor and type of capacitor (Spherical, Cylindrical)

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The radius of a metallic sphere if its capacitance is $1/9\,F$,is

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