The radius of the first orbit of hydrogen is $r_{H}$,and the energy in the ground state is $-13.6 \text{ eV}$. Considering a $\mu^{-}$-particle with a mass $207 m_e$ revolving around a proton as in a hydrogen atom,the energy and radius of the proton and $\mu^{-}$-combination respectively in the first orbit are (assume the nucleus to be stationary):

  • A
    $-13.6 \times 207 \text{ eV}, \frac{r_{H}}{207}$
  • B
    $-207 \times 13.6 \text{ eV}, 207 r_{H}$
  • C
    $-\frac{13.6}{207} \text{ eV}, \frac{r_{H}}{207}$
  • D
    $-\frac{13.6}{207} \text{ eV}, 207 r_{H}$

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In a hydrogen atom,the electron and proton are bound at a distance of about $0.53 \; \mathring{A}$.
$(a)$ Estimate the potential energy of the system in $eV$,taking the zero of the potential energy at infinite separation of the electron from the proton.
$(b)$ What is the minimum work required to free the electron,given that its kinetic energy in the orbit is half the magnitude of potential energy obtained in $(a)$?
$(c)$ What are the answers to $(a)$ and $(b)$ above if the zero of potential energy is taken at $1.06 \; \mathring{A}$ separation?

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