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(A) The radius of an electron orbit in a hydrogen-like atom is given by the formula: $r_n = n^2 a_0$,where $n$ is the principal quantum number and $a_

Vedclass · Accepted Answer

$8.48 	imes 10^{-10} \ m$

Vedclass · Answer

(A) The radius of an electron orbit in a hydrogen-like atom is given by the formula: $r_n = n^2 a_0$,where $n$ is the principal quantum number and $a_0$ is the Bohr radius $(5.3 	imes 10^{-11} \ m)$.For the $n=4$ state,we substitute the values into the formula:$r_4 = (4)^2 	imes (5.3 	imes 10^{-11} \ m)$$r_4 = 16 	imes 5.3 	imes 10^{-11} \ m$$r_4 = 84.8 	imes 10^{-11} \ m$$r_4 = 8.48 	imes 10^{-10} \ m$Therefore,the correct option is $A$.

The radius of the innermost electron orbit of a hydrogen atom is $5.3 \times 10^{-11} \ m$. What is the radius of the $n=4$ state?

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