The range of the function f(x)=sin [x],where | vedclass

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(D) Given the function $f(x) = \sin [x]$ for $-\frac{\pi}{4} < x < \frac{\pi}{4}$. We know that $\frac{\pi}{4} \approx 0.785$ and $-\frac{\pi}{4} \app

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$\{0, -\sin 1\}$

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(D) Given the function $f(x) = \sin [x]$ for $-\frac{\pi}{4} We know that $\frac{\pi}{4} \approx 0.785$ and $-\frac{\pi}{4} \approx -0.785$. The interval for $x$ is $(-0.785, 0.785)$. For $x \in [0, 0.785)$,the greatest integer value $[x] = 0$. Thus,$f(x) = \sin(0) = 0$. For $x \in (-0.785, 0)$,the greatest integer value $[x] = -1$. Thus,$f(x) = \sin(-1) = -\sin(1)$. Therefore,the range of the function is $\{0, -\sin 1\}$.

The range of the function $f(x)=\sin [x]$,where $-\frac{\pi}{4} < x < \frac{\pi}{4}$ and $[x]$ denotes the greatest integer $\leq x$,is

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