The rate constant $(K')$ of one reaction is double the rate constant $(K'')$ of another reaction. What is the relationship between the corresponding activation energies of the two reactions (${E_a}'$ and ${E_a}''$)?

  • A
    ${E_a}' > {E_a}''$
  • B
    ${E_a}' = {E_a}''$
  • C
    ${E_a}' < {E_a}''$
  • D
    ${E_a}' = 4{E_a}''$

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