The rate constant of a zero order reaction is $2.0 \times 10^{-2} \ mol \ L^{-1} \ s^{-1}$. If the concentration of the reactant after $25 \ s$ is $0.5 \ M$,then find the initial concentration of the reactant. (in $M$)
- A$0.5$
- B$1.25$
- C$12.5$
- D$1.0$
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Which of the following is correct with respect to the graph given?
$\begin{aligned} & [R]=\text{Concentration at time } t \\ & [R]_0=\text{Initial concentration} \end{aligned}$
$\begin{aligned} & [R]=\text{Concentration at time } t \\ & [R]_0=\text{Initial concentration} \end{aligned}$
If the rate constant $(K)$ of a reaction is $1.6 \times 10^{-3} \ mol \ L^{-1} \ min^{-1}$,the order of reaction is
Medium
View SolutionThe decomposition of $NH_3$ on the platinum surface is a zero-order reaction. If $K = 2.5 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$,what will be the rate of production of $H_2$ in $mol \ L^{-1} \ s^{-1}$ unit?
Consider the data given below for the hypothetical reaction $A \to X$:
$Time \ (s)$ $Rate \ (mol \ L^{-1} s^{-1})$ $0$ $1.60 \times 10^{-2}$ $10$ $1.60 \times 10^{-2}$ $20$ $1.60 \times 10^{-2}$ $30$ $1.60 \times 10^{-2}$
From the above data,the order of the reaction is:
| $Time \ (s)$ | $Rate \ (mol \ L^{-1} s^{-1})$ |
|---|---|
| $0$ | $1.60 \times 10^{-2}$ |
| $10$ | $1.60 \times 10^{-2}$ |
| $20$ | $1.60 \times 10^{-2}$ |
| $30$ | $1.60 \times 10^{-2}$ |
From the above data,the order of the reaction is:
Medium
View SolutionIn a zero-order reaction,if the initial concentration of the reactant is doubled,the time required for half the reactant to be consumed:
DifficultKVPY 2011
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