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(B) According to Poiseuille's law,the rate of flow of a liquid (volume per unit time) through a cylindrical tube of radius $r$ and length $l$ under a

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$\frac{1}{8}$

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(B) According to Poiseuille's law,the rate of flow of a liquid (volume per unit time) through a cylindrical tube of radius $r$ and length $l$ under a pressure difference $P$ is given by the formula:$V = \frac{\pi P r^4}{8 \eta l}$Comparing this with the given equation $V = \frac{\pi Q P r^4}{\eta l}$,we can equate the coefficients:$\frac{\pi P r^4}{8 \eta l} = \frac{\pi Q P r^4}{\eta l}$By canceling the common terms $\pi, P, r^4, \eta,$ and $l$ from both sides,we get:$\frac{1}{8} = Q$Therefore,the value of $Q$ is $\frac{1}{8}$.

The rate of flow of liquid in a tube of radius $r$ and length $l$,whose ends are maintained at a pressure difference $P$,is given by $V = \frac{\pi Q P r^4}{\eta l}$,where $\eta$ is the coefficient of viscosity. What is the value of $Q$?

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