The rate of the simple reaction,$2NO + O_2 \to 2NO_2$,when the volume of the reaction vessel is doubled:

  • A
    will grow eight times of its initial rate
  • B
    reduce to one-eighth of its initial rate
  • C
    will grow four times of its initial rate
  • D
    reduce to one-fourth of its initial rate

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If $r = k[A]^2[B]$ is the rate law equation for the reaction $A + B \rightarrow C$,at $[A] = 1 \ M$ and $[B] = 0.2 \ M$,calculate the rate of reaction if the rate constant is $6.25 \ M^{-2} \ s^{-1}$. (in $M \ s^{-1}$)

The following results have been obtained during the kinetic studies of the reaction:
$2 A + B \rightarrow C + D$
Experiment $[A] / mol \, L^{-1}$ $[B] / mol \, L^{-1}$ Initial rate of formation of $D / mol \, L^{-1} \, min^{-1}$
$I$ $0.1$ $0.1$ $6.0 \times 10^{-3}$
$II$ $0.3$ $0.2$ $7.2 \times 10^{-2}$
$III$ $0.3$ $0.4$ $2.88 \times 10^{-1}$
$IV$ $0.4$ $0.1$ $2.40 \times 10^{-2}$

Determine the rate law and the rate constant for the reaction.

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