The ratio C_P / C_V for a gas mixture consist | vedclass

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(C) For Helium $(He)$: Molar mass $M_1 = 4 \ g/mol$,degrees of freedom $f_1 = 3$,mass $m_1 = 8 \ g$. Number of moles $n_1 = 8/4 = 2 \ mol$.For Oxygen

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$27/17$

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(C) For Helium $(He)$: Molar mass $M_1 = 4 \ g/mol$,degrees of freedom $f_1 = 3$,mass $m_1 = 8 \ g$. Number of moles $n_1 = 8/4 = 2 \ mol$.For Oxygen $(O_2)$: Molar mass $M_2 = 32 \ g/mol$,degrees of freedom $f_2 = 5$,mass $m_2 = 16 \ g$. Number of moles $n_2 = 16/32 = 0.5 \ mol$.The average degrees of freedom $f_{av}$ is given by:$f_{av} = \frac{n_1 f_1 + n_2 f_2}{n_1 + n_2} = \frac{(2 	imes 3) + (0.5 	imes 5)}{2 + 0.5} = \frac{6 + 2.5}{2.5} = \frac{8.5}{2.5} = \frac{17}{5} = 3.4$.The ratio of specific heats $\gamma_{av} = 1 + \frac{2}{f_{av}} = 1 + \frac{2}{3.4} = 1 + \frac{20}{34} = 1 + \frac{10}{17} = \frac{27}{17}$.

The ratio $C_P / C_V$ for a gas mixture consisting of $8 \ g$ of helium and $16 \ g$ of oxygen is

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