The ratio of sigma-bond and pi-bond in tetrac | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The structure of tetracyanoethylene is $(CN)_2C=C(CN)_2$.In this molecule,there is a central $C=C$ double bond (one $\sigma$ and one $\pi$ bond).E

Vedclass · Accepted Answer

$1 : 1$

Vedclass · Answer

(B) The structure of tetracyanoethylene is $(CN)_2C=C(CN)_2$.In this molecule,there is a central $C=C$ double bond (one $\sigma$ and one $\pi$ bond).Each of the four $C-CN$ bonds contains one $\sigma$ bond.Each of the four $C \equiv N$ triple bonds contains one $\sigma$ bond and two $\pi$ bonds.Total $\sigma$-bonds = $1$ (central $C-C$) + $4$ $(C-CN)$ + $4$ $(C-N)$ = $9$.Total $\pi$-bonds = $1$ (central $C=C$) + $4 	imes 2$ $(C \equiv N)$ = $9$.The ratio of $\sigma$-bond to $\pi$-bond is $9 : 9$,which simplifies to $1 : 1$.

The ratio of $\sigma$-bond and $\pi$-bond in tetracyanoethylene is

Similar Questions

Which one of the following bonds has the highest average bond energy $(kcal/mol)$?

Choose the incorrect statement.

The incorrect statement is :-

Which of the following molecules does not form in the $I^{st}$ excited state of the central atom?

Which of the following is the correct decreasing order of bond length for $N_2$, $O_2$, and $Cl_2$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module