The ratio of electrostatic and gravitational | vedclass

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Question

(A) The gravitational force between an electron and a proton is given by $F_G = \frac{G m_e m_p}{r^2}$.Substituting the values: $F_G = \frac{6.7 	ime

Vedclass · Accepted Answer

$2.36 	imes 10^{39}$

Vedclass · Answer

(A) The gravitational force between an electron and a proton is given by $F_G = \frac{G m_e m_p}{r^2}$.Substituting the values: $F_G = \frac{6.7 	imes 10^{-11} 	imes 9.1 	imes 10^{-31} 	imes 1.6 	imes 10^{-27}}{(5 	imes 10^{-11})^2} \approx 3.9 	imes 10^{-47} \, N$.The electrostatic force between an electron and a proton is given by $F_e = \frac{1}{4\pi \epsilon_0} \frac{e^2}{r^2}$.Substituting the values: $F_e = \frac{9 	imes 10^9 	imes (1.6 	imes 10^{-19})^2}{(5 	imes 10^{-11})^2} \approx 9.22 	imes 10^{-8} \, N$.The ratio of electrostatic to gravitational force is $\frac{F_e}{F_G} = \frac{9.22 	imes 10^{-8}}{3.9 	imes 10^{-47}} \approx 2.36 	imes 10^{39}$.

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