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(B) The heat dissipated per second is the power $P$ consumed by the resistor,given by $P = I^2 R = \frac{V^2}{R}$.Since the resistors $5 \Omega$ and $

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$2: 1$

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(B) The heat dissipated per second is the power $P$ consumed by the resistor,given by $P = I^2 R = \frac{V^2}{R}$.Since the resistors $5 \Omega$ and $10 \Omega$ are connected in parallel,the potential difference $V$ across both is the same.Therefore,the ratio of power dissipated is $\frac{P_1}{P_2} = \frac{V^2 / R_1}{V^2 / R_2} = \frac{R_2}{R_1}$.Substituting the values $R_1 = 5 \Omega$ and $R_2 = 10 \Omega$,we get $\frac{P_1}{P_2} = \frac{10}{5} = \frac{2}{1}$.Thus,the ratio is $2: 1$.

The ratio of heat dissipated per second through the resistance $5 \Omega$ and $10 \Omega$ in the circuit given below is:

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