The ratio of heats generated through shunt and galvanometer is $7: 5$ when they are connected to make an ammeter. If the resistance of the galvanometer is $112 \Omega$,then the resistance of the shunt is: (in $\Omega$)

  • A
    $80$
  • B
    $8$
  • C
    $15.6$
  • D
    $1.56$

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