The ratio of the ionization energy of a Bohr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The ionization energy $(E_{ion})$ of a hydrogen-like atom is given by the formula:$E_{ion} = 13.6 	imes Z^2 	ext{ eV}$where $Z$ is the atomic nu

Vedclass · Accepted Answer

$1:9$

Vedclass · Answer

(C) The ionization energy $(E_{ion})$ of a hydrogen-like atom is given by the formula:$E_{ion} = 13.6 	imes Z^2 	ext{ eV}$where $Z$ is the atomic number of the atom.For a hydrogen atom,$Z_H = 1$. Thus,$(E_{ion})_H = 13.6 	imes (1)^2 = 13.6 	ext{ eV}$.For a lithium atom (hydrogen-like,$Li^{2+}$),$Z_{Li} = 3$. Thus,$(E_{ion})_{Li} = 13.6 	imes (3)^2 = 13.6 	imes 9 	ext{ eV}$.The ratio of the ionization energy of the hydrogen atom to the lithium atom is:$\frac{(E_{ion})_H}{(E_{ion})_{Li}} = \frac{13.6 	imes (1)^2}{13.6 	imes (3)^2} = \frac{1}{9}$.Therefore,the ratio is $1:9$.

The ratio of the ionization energy of a Bohr hydrogen atom to that of a Bohr hydrogen-like lithium atom is:

Similar Questions

$A$ photon and an electron have equal energy $E$. The ratio $\lambda_{\text{photon}} / \lambda_{\text{electron}}$ is proportional to:

Two charges $+3.2 \times 10^{-19} \, C$ and $-3.2 \times 10^{-19} \, C$ kept $2.4 \, \mathring{A}$ apart form a dipole. If it is placed in a uniform electric field of intensity $4 \times 10^5 \, V/m$,what will be its potential energy in stable equilibrium?

Which is the infectious stage of $Plasmodium$?

Six faces of an unbiased die are numbered with $2, 3, 5, 7, 11$ and $13$. If two such dice are thrown,then the probability that the sum on the uppermost faces of the dice is an odd number is

Which of the following electronic configurations is not possible according to Hund's rule?

Vedclass Test Series

Exam Paper Generator

Online Exam Module