The ratio of radii of two wires is $1: 2$ and the ratio of the densities of their materials is $1: 4$. If the same tension is applied to both wires,then the ratio of the speed of transverse waves produced in them is

$A$ uniform metal wire has length $L$,mass $M$,and density $\rho$. It is under tension $T$,and $v$ is the speed of a transverse wave along the wire. The area of cross-section of the wire is:

$A$ composite string is made up by joining two strings of different mass per unit length,$\mu$ and $4\mu$. The composite string is under the same tension $T$. $A$ transverse wave pulse,$Y = (6 \text{ mm}) \sin(5t + 40x)$,where $t$ is in seconds and $x$ is in meters,is sent along the lighter string towards the joint. The joint is at $x = 0$. The equation of the wave pulse reflected from the joint is:

$A$ steel wire has a length of $12 \ m$ and a mass of $2.10 \ kg$. What will be the speed of a transverse wave on this wire when a tension of $2.06 \times 10^4 \ N$ is applied (in $m/s$)?

$A$ string of mass $0.1 \, kg$ is under a tension $1.6 \, N$. The length of the string is $1 \, m$. $A$ transverse wave starts from one end of the string. The time taken by the wave to reach the other end is (in $s$.)

$A$ string of mass $0.2 \ kg$ is under a tension of $2.5 \ N$. The length of the string is $2 \ m$. $A$ transverse wave starts from one end of the string. The time taken by the wave to reach the other end is: (in $s$)