The ratio of rates of diffusion of helium (He | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Graham's Law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $r \propt

Vedclass · Accepted Answer

$1 : \sqrt{2}$

Vedclass · Answer

(A) According to Graham's Law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $r \propto \frac{1}{\sqrt{M}}$.Molecular mass of $H_2$ $(M_{H_2})$ = $2 \ g/mol$.Molecular mass of $He$ $(M_{He})$ = $4 \ g/mol$.$\frac{r_{He}}{r_{H_2}} = \sqrt{\frac{M_{H_2}}{M_{He}}} = \sqrt{\frac{2}{4}} = \sqrt{\frac{1}{2}} = \frac{1}{\sqrt{2}}$.Therefore,the ratio is $1 : \sqrt{2}$.

The ratio of rates of diffusion of helium $(He)$ to hydrogen $(H_2)$.

Similar Questions

Equal amounts of two gases of molecular weights $4$ and $40$ are mixed. The pressure of the mixture is $1.1 \ atm$. What will be the partial pressure of the lighter gas in the mixture (in $atm$)?

What is viscosity?

The ratio of the rate of diffusion of $SO_2$ to $CH_4$ is

$A$ mixture of $0.5 \text{ mol}$ $N_2$ gas, $1.0 \text{ mol}$ $O_2$ gas and $1.5 \text{ mol}$ $H_2$ gas exerts a total pressure of $18 \text{ bar}$. Find the partial pressure of $O_2(g)$. (in $\text{ bar}$)

The atmospheric pressure is the sum of the

Vedclass Test Series

Exam Paper Generator

Online Exam Module