The ratio of root mean square velocity of H_2 | vedclass

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(C) The formula for root mean square velocity is $v_{rms} = \sqrt{\frac{3RT}{M}}$.Therefore,the ratio is given by $\frac{v_{H_2}}{v_{O_2}} = \sqrt{\fr

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(C) The formula for root mean square velocity is $v_{rms} = \sqrt{\frac{3RT}{M}}$.Therefore,the ratio is given by $\frac{v_{H_2}}{v_{O_2}} = \sqrt{\frac{T_{H_2}}{M_{H_2}} 	imes \frac{M_{O_2}}{T_{O_2}}}$.Substituting the given values: $T_{H_2} = 50 \ K$,$M_{H_2} = 2 \ g/mol$,$T_{O_2} = 800 \ K$,and $M_{O_2} = 32 \ g/mol$.$\frac{v_{H_2}}{v_{O_2}} = \sqrt{\frac{50}{2} 	imes \frac{32}{800}} = \sqrt{25 	imes \frac{1}{25}} = \sqrt{1} = 1$.

The ratio of root mean square velocity of $H_2$ at $50 \ K$ to that of $O_2$ at $800 \ K$ is

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