The ratio of surface tensions of mercury and water is given to be $7.5$ while the ratio of their densities is $13.6$. Their contact angles with glass are close to $135^o$ and $0^o$,respectively. It is observed that mercury gets depressed by an amount $h$ in a capillary tube of radius $r_1$,while water rises by the same amount $h$ in a capillary tube of radius $r_2$. The ratio $(r_1/r_2)$ is then close to:

This question has Statement-$I$ and Statement-$II$. Of the four choices given after the statements,choose the one that best describes the two statements.
Statement-$I$: $A$ capillary is dipped in a liquid and liquid rises to a height $h$ in it. As the temperature of the liquid is raised,the height $h$ increases (if the density of the liquid and the angle of contact remain the same).
Statement-$II$: Surface tension of a liquid decreases with the rise in its temperature.

The angle of contact between glass and water is $0^\circ$ and it rises in a capillary up to $6 \text{ cm}$ when its surface tension is $70 \text{ dynes/cm}$. Another liquid of surface tension $140 \text{ dynes/cm}$,angle of contact $60^\circ$ and relative density $2$ will rise in the same capillary by ........ $\text{cm}$.

Three liquids have the same surface tension and have densities $\rho_1, \rho_2$, and $\rho_3$ $(\rho_1 > \rho_2 > \rho_3)$. In three identical capillaries, the rise of liquid is the same. The corresponding angles of contact $\theta_1, \theta_2$, and $\theta_3$ are related as:

In a capillary,the pressure below the curved surface of water will be:

When a capillary tube is dipped vertically in water,the rise of water in the capillary is $h$. The angle of contact is $0^{\circ}$. Now,the tube is depressed so that its length above the water surface is $\frac{h}{3}$. The new apparent angle of contact is $(\cos 0^{\circ} = 1)$.