The ratio of the mass percentages of C and H | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given mass ratios: $C : H = 4 : 1$ and $C : O = 3 : 4$.To find the combined mass ratio $C : H : O$,we equate the $C$ part: $C : H = 12 : 3$ and $C

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(D) Given mass ratios: $C : H = 4 : 1$ and $C : O = 3 : 4$.To find the combined mass ratio $C : H : O$,we equate the $C$ part: $C : H = 12 : 3$ and $C : O = 12 : 16$.Thus,$C : H : O = 12 : 3 : 16$.Dividing by atomic masses $(C=12, H=1, O=16)$,the mole ratio is $C : H : O = (12/12) : (3/1) : (16/16) = 1 : 3 : 1$.The empirical formula is $CH_3O$. Since the compound is a saturated acyclic organic compound,the molecular formula is $C_2H_6O_2$ (e.g.,ethylene glycol).The combustion reaction is: $C_2H_6O_2 + 2.5 O_2 \longrightarrow 2 CO_2 + 3 H_2O$.For $1$ mole of $X$,$2.5$ moles of $O_2$ are required.For $2$ moles of $X$,the moles of $O_2$ required $= 2 	imes 2.5 = 5$ moles.

The ratio of the mass percentages of $C$ and $H$ and $C$ and $O$ of a saturated acyclic organic compound $X$ are $4 : 1$ and $3 : 4$ respectively. Then,the moles of oxygen gas required for complete combustion of two moles of organic compound $X$ is

Similar Questions

$A$ compound contains $2.2 \ g$ of phosphorus and $1.24 \ g$ of sulfur. What is its empirical formula?

$A$ pure compound contains $2.4 \ g$ of $C$,$1.2 \times 10^{23}$ atoms of $H$,and $0.2 \ mol$ of oxygen atoms. Its empirical formula is

$A$ sample of a hydrate of barium chloride weighing $61 \ g$ was heated until all the water of hydration was removed. The dried sample weight is $52 \ g$. The formula of the hydrated salt is: (atomic mass: $Ba = 137 \ amu, Cl = 35.5 \ amu$)

An oxygen-containing organic compound was found to contain $52 \%$ carbon and $13 \%$ hydrogen. Its vapour density is $23$. The compound reacts with sodium metal to liberate hydrogen. $A$ functional isomer of this compound is

If two compounds have the same empirical formula but different molecular formulae,they must have:

Vedclass Test Series

Exam Paper Generator

Online Exam Module