The ratio of the nuclear radii of elements wi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The nuclear radius $R$ is given by the formula $R = R_0 A^{1/3}$,where $A$ is the mass number and $R_0$ is a constant.Given mass numbers are $A_1

Vedclass · Accepted Answer

$6: 5$

Vedclass · Answer

(C) The nuclear radius $R$ is given by the formula $R = R_0 A^{1/3}$,where $A$ is the mass number and $R_0$ is a constant.Given mass numbers are $A_1 = 216$ and $A_2 = 125$.The ratio of the radii is $\frac{R_1}{R_2} = \frac{R_0 (A_1)^{1/3}}{R_0 (A_2)^{1/3}}$.Substituting the values,$\frac{R_1}{R_2} = \frac{(216)^{1/3}}{(125)^{1/3}}$.Since $216 = 6^3$ and $125 = 5^3$,we have $\frac{R_1}{R_2} = \frac{6}{5}$ or $6:5$.

The ratio of the nuclear radii of elements with mass numbers $216$ and $125$ is

Similar Questions

The nuclear radius is given by $R = r_0 A^{1/3}$,where $r_0$ is a constant and $A$ is the atomic mass number. Then,the nuclear mass density of $^{238}U$ is

Show that the volume of a nucleus is proportional to its atomic mass number $A$.

Nuclear forces are

As compared to a $^{12}C$ atom,a $^{14}C$ atom has:

If the radii of ${}_{13}^{27}Al$ and ${}_{30}^{64}Zn$ nuclei are $R_{1}$ and $R_{2}$ respectively,then $\frac{R_{1}}{R_{2}} = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module