The ratio of the speeds of Aman,Kamal,and Man | vedclass

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(D) We know that for a constant distance,speed is inversely proportional to time,i.e.,$	ext{Speed} \propto \frac{1}{	ext{Time}}$.Given the ratio of

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$15: 12: 10$

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(D) We know that for a constant distance,speed is inversely proportional to time,i.e.,$	ext{Speed} \propto \frac{1}{	ext{Time}}$.Given the ratio of speeds of Aman,Kamal,and Manan is $4: 5: 6$.Therefore,the ratio of time taken is the reciprocal of the speed ratio: $\frac{1}{4}: \frac{1}{5}: \frac{1}{6}$.To simplify this ratio,we find the Least Common Multiple $(LCM)$ of the denominators $4, 5,$ and $6$,which is $60$.Multiplying each term by $60$,we get: $(\frac{1}{4} 	imes 60) : (\frac{1}{5} 	imes 60) : (\frac{1}{6} 	imes 60)$.This results in $15: 12: 10$.Thus,the ratio of time taken is $15: 12: 10$.

The ratio of the speeds of Aman,Kamal,and Manan is $4: 5: 6$ respectively. What is the ratio of time taken by Aman,Kamal,and Manan respectively to cover the same distance?

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