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(B) The velocity of an electron in the $n^{th}$ Bohr orbit is given by the formula $v_n = \frac{Ze^2}{2 \varepsilon_0 nh}$.From this expression,we can

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$2: 1$

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(B) The velocity of an electron in the $n^{th}$ Bohr orbit is given by the formula $v_n = \frac{Ze^2}{2 \varepsilon_0 nh}$.From this expression,we can see that the velocity is inversely proportional to the principal quantum number $n$,i.e.,$v_n \propto \frac{1}{n}$.For the first orbit,$n_1 = 1$,and for the second orbit,$n_2 = 2$.Therefore,the ratio of the velocities is $\frac{v_1}{v_2} = \frac{n_2}{n_1} = \frac{2}{1}$.Thus,the ratio is $2:1$.

The ratio of the velocity of the electron in the first Bohr orbit to that in the second Bohr orbit of a hydrogen atom is

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