The reaction H_2S + H_2O_2 to S + 2H_2O manif | vedclass

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(C) In the reaction $H_2S + H_2O_2 	o S + 2H_2O$,the oxidation state of sulfur in $H_2S$ changes from $-2$ to $0$ (oxidation).Simultaneously,the oxid

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Oxidising nature of $H_2O_2$

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(C) In the reaction $H_2S + H_2O_2 	o S + 2H_2O$,the oxidation state of sulfur in $H_2S$ changes from $-2$ to $0$ (oxidation).Simultaneously,the oxidation state of oxygen in $H_2O_2$ changes from $-1$ to $-2$ (reduction).Since $H_2O_2$ undergoes reduction,it acts as an oxidizing agent.Therefore,the reaction manifests the oxidizing nature of $H_2O_2$.Hence,option $C$ is correct.

The reaction $H_2S + H_2O_2 \to S + 2H_2O$ manifests

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