The reaction $Zn^{2+} + 2e^{-} \to Zn$ has a standard electrode potential of $-0.76 \ V$. This means:

  • A
    $Zn$ cannot replace hydrogen from acids
  • B
    $Zn$ is a reducing agent
  • C
    $Zn$ is an oxidizing agent
  • D
    $Zn^{2+}$ is a reducing agent

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Given electrode potentials:
$Fe^{3+} + e^- \to Fe^{2+}$; $E^o = 0.771 \, V$
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