The reaction of $Pb(NO_3)_2$ and $NaCl$ in water produces a precipitate that dissolves upon the addition of $HCl$ of appropriate concentration. The dissolution of the precipitate is due to the formation of

  • A
    $PbCl_2$
  • B
    $PbCl_4$
  • C
    $[PbCl_4]^{2-}$
  • D
    $[PbCl_6]^{2-}$

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