The reaction 2 C_6H_6 + CH_2Cl_2 xrightarrow{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction is a Friedel-Crafts alkylation. Benzene reacts with dichloromethane $(CH_2Cl_2)$ in the presence of a Lewis acid catalyst like $AlCl_

Vedclass · Accepted Answer

$Ph-CH_2-Ph$

Vedclass · Answer

(B) The reaction is a Friedel-Crafts alkylation. Benzene reacts with dichloromethane $(CH_2Cl_2)$ in the presence of a Lewis acid catalyst like $AlCl_3$. The electrophile $CH_2Cl^{+}$ attacks the benzene ring to form benzyl chloride $(Ph-CH_2Cl)$. This intermediate then reacts with another molecule of benzene to form diphenylmethane $(Ph-CH_2-Ph)$. The overall reaction is: $2 C_6H_6 + CH_2Cl_2 \xrightarrow{AlCl_3} Ph-CH_2-Ph + 2 HCl$.

The reaction $2 C_6H_6 + CH_2Cl_2 \xrightarrow{AlCl_3, \Delta} ?$ gives the major product:

Similar Questions

The compound that is most reactive towards electrophilic nitration is

The product obtained from the ozonolysis of benzene is........

Identify the number of aromatic compounds from the following structures:
$(I)$ Cyclopentadiene
$(II)$ Cyclooctatetraene
$(III)$ Borazine $(B_3N_3H_6)$
$(IV)$ $1,4-$diboracyclohexa$-2,5-$diene

Enumerate different aromatic electrophilic substitution reactions and provide the reactions that show how the electrophiles $(E^{+})$ are formed.

Why is benzene extraordinarily stable even though it contains three double bonds?

Vedclass Test Series

Exam Paper Generator

Online Exam Module