The reaction in which Delta H Delta U is | vedclass

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(D) The relationship between enthalpy change and internal energy change is given by $\Delta H = \Delta U + \Delta n_g RT$. For $\Delta H > \Delta U$,t

Vedclass · Accepted Answer

$CaCO_{3(s)} \rightarrow CaO_{(s)} + CO_{2(g)}$

Vedclass · Answer

(D) The relationship between enthalpy change and internal energy change is given by $\Delta H = \Delta U + \Delta n_g RT$. For $\Delta H > \Delta U$,the value of $\Delta n_g$ (change in the number of moles of gaseous products and reactants) must be positive,i.e.,$\Delta n_g > 0$. In option $(d)$: $CaCO_{3(s)} ightarrow CaO_{(s)} + CO_{2(g)}$. Here,$\Delta n_g = (	ext{moles of gaseous products}) - (	ext{moles of gaseous reactants}) = 1 - 0 = 1$. Since $\Delta n_g$ is positive,$\Delta H > \Delta U$.

The reaction in which $\Delta H > \Delta U$ is

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