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(D) The reaction sequence is as follows:$1$. Reductive ozonolysis of ethene $(CH_2=CH_2)$ gives formaldehyde $(HCHO)$ as product $A$.$CH_2=CH_2 \xrigh

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Cannizzaro reaction

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(D) The reaction sequence is as follows:$1$. Reductive ozonolysis of ethene $(CH_2=CH_2)$ gives formaldehyde $(HCHO)$ as product $A$.$CH_2=CH_2 \xrightarrow[2. Zn/H_2O]{1. O_3} 2HCHO (A)$$2$. Formaldehyde $(HCHO)$ lacks $\alpha$-hydrogen atoms,so it undergoes a self-oxidation-reduction reaction (disproportionation) in the presence of concentrated $NaOH$,known as the Cannizzaro reaction.$2HCHO + NaOH (conc.) \rightarrow CH_3OH (B) + HCOONa (C)$Here,$B$ is methanol (alcohol) and $C$ is sodium formate (sodium salt of carboxylic acid).Therefore,the reaction of $A$ to give $B$ and $C$ is an example of the Cannizzaro reaction.

Column-$I$ (Reactions)	Column-$II$ (Reagents)
$(i)$. Benzophenone $\rightarrow$ Diphenylmethane	$(a)$. $LiAlH_4$
$(ii)$. Benzaldehyde $\rightarrow$ $1-$Phenylethanol	$(b)$. $DIBAL-H$
$(iii)$. Cyclohexanone $\rightarrow$ Cyclohexanol	$(c)$. $Zn(Hg) / \text{Conc. } HCl$
$(iv)$. Phenyl benzoate $\rightarrow$ Benzaldehyde	$(d)$. $CH_3MgBr, H_2O$

The reaction of $A$ to give $B$ and $C$ as shown in the reaction scheme is an example of:
$CH_2=CH_2$ $\xrightarrow[2. Zn/H_2O]{1. O_3} A$ $\xrightarrow{Conc. NaOH} B + C$
(Where $B$ is an alcohol and $C$ is a sodium salt of a carboxylic acid)

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The reaction of $A$ to give $B$ and $C$ as shown in the reaction scheme is an example of:$CH_2=CH_2$ $\xrightarrow[2. Zn/H_2O]{1. O_3} A$ $\xrightarrow{Conc. NaOH} B + C$(Where $B$ is an alcohol and $C$ is a sodium salt of a carboxylic acid)