The reaction of elemental $P_4$ and aqueous $NaOH$ gives

  • A
    $PH_3, \, NaH_2PO_2$
  • B
    $PH_3, \, Na_3PO_4$
  • C
    $NaHPO_4, \, Na_3PO_4$
  • D
    $Na_3P, \, Na_3PO_4$

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