The reaction of propene with HOCl (Cl_2 + H_2 | vedclass

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Question

(D) The reaction of propene with $HOCl$ involves the electrophilic attack of $Cl^+$ on the double bond. The $Cl^+$ ion attacks the double bond to form

Vedclass · Accepted Answer

$CH_3-CH^+-CH_2-Cl$

Vedclass · Answer

(D) The reaction of propene with $HOCl$ involves the electrophilic attack of $Cl^+$ on the double bond. The $Cl^+$ ion attacks the double bond to form a cyclic chloronium ion intermediate,which is then opened by the nucleophilic attack of $H_2O$ or $OH^-$. However,in terms of carbocation character during the ring opening,the positive charge is stabilized on the more substituted carbon atom. The intermediate formed is $CH_3-CH^+-CH_2-Cl$.

The reaction of propene with $HOCl$ $(Cl_2 + H_2O)$ proceeds through the intermediate $:$

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